Suatu larutan dibuat dengan melarutkan 15 gram NaCl ke dalam 85 gram air. Hitunglah persen massa (% massa) NaCl dalam larutan tersebut, dan jelaskan langkah-langkah perhitungannya

t 2 1 ​ ​ = 5730 N 0 ​ = 120 g t = 2 t 2 1 ​ ​ = 2 ⋅ 5730 = 11460 N ( t ) = ? N ( t ) = N 0 ​ ( 2 1 ​ ) t 2 1 ​ ​ t ​ N ( 11460 ) = 120 ⋅ ( 2 1 ​ ) 5730 11460 ​ N ( 11460 ) = 120 ⋅ ( 2 1 ​ ) 2 N ( 11460 ) = 120 ⋅ 4 1 ​ N ( 11460 ) = 30 g

Answered by konrad509 | 2024-06-10

After one half-life . . . 1/2 of the total parent material
After another half-life . . . 1/2 of the half remains = 1/4 of the total original parent
If the original parent is 120 grams, then (1/4 x 20) = 30 grams remains after 2 half-lives. It makes no difference what the substance is, or how long its half-life is.

Answered by AL2006 | 2024-06-10

After 2 half-lives of carbon-14, which lasts 5,730 years each, 30 grams will remain from an initial sample of 120 grams. The answer is C. 30 grams.
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Answered by konrad509 | 2024-08-23

Jawaban:Ada di penjelasan.Penjelasan:Massa NaCl = 15 gramMassa larutan = Massa NaCl + Massa pelarut (air)Massa larutan = 15 gram + 85 gram = 100 gram%massa NaCl = ((Massa NaCl)/(Massa laruran)) x (100%)%massa NaCl = (15 gram/100 gram) x (100%)%massa NaCl = 15%

Answered by jouharidimas | 2025-07-04