the partial pressure of argon is:
1.63-0.71= 0.92 atm
1.63 atm - 0.71 atm = 0.92 atm
The partial pressure of argon gas in the mixture is 0.92 atm, calculated by subtracting the partial pressure of neon from the total pressure. Using Dalton's Law of Partial Pressures allows us to find individual gas pressures in a mixture. Therefore, we find that P_argon = 1.63 atm - 0.71 atm = 0.92 atm.
;
Jawaban:-3, -2, -1, 0,1,2,3,4,5Penjelasan dengan langkah-langkah:semoga membantu kak