The question asks us to determine the number of different lunches possible for a student who chooses exactly 1 sandwich, 1 soup, 1 salad, and 1 drink from a given set of options in the school cafeteria. To solve this, we use the fundamental principle of counting which states that if there are n ways to do one thing, and m ways to do another, then there are n x m ways to do both.
In this case, the student can choose from 3 sandwiches, 3 soups, 4 salads, and 2 drinks. Therefore, we simply multiply the number of options for each selection together:
Sandwich selection = 3 optionsSoup selection = 3 optionsSalad selection = 4 optionsDrink selection = 2 options
By multiplying these together (3 x 3 x 4 x 2), we arrive at the total number of different lunch combinations possible which is 72.
There are 72 different lunch combinations possible in the school cafeteria when choosing 1 sandwich, 1 soup, 1 salad, and 1 drink. This is calculated by multiplying the number of options for each food and drink item together. Thus, the formula used is 3 sandwiches x 3 soups x 4 salads x 2 drinks = 72 total lunch combinations.
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