hasil dari -13 x 13 : (-3)

This problem has more holes than swiss cheese.
ASSUME that the time he drives only depends on the distance he covers, and has nothing to do with his speed or how he drives.
The race rules say he has to cover at least 50 km, so the minimum time he can drive is the solution to [ 50 = 3t + 47 ] Subtract 47 from each side: 3 = 3t Divide each side by 3 : 1 = t minimum
He has fuel for exactly 53 km, so the maximum time he can drive is the solution to [ 53 = 3t + 47 ] Subtract 47 from each side : 6 = 3t Divide each side by 3 : 2 = t ** **maximum

Answered by AL2006 | 2024-06-10

Alan can drive for a minimum of 1 hour and a maximum of 2 hours. The calculations use the distance function to determine these times based on the race requirements of covering at least 50 km and a maximum of 53 km. The equations are based on the distance formula S ( t ) = 3 t + 47 .
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Answered by AL2006 | 2024-12-23

•°• Hasil dari -13 × 13 : (-3) adalah 56,33.[tex] \\ \\ [/tex]Penjelasan dengan langkah-langkah:-13 × 13 : (-3)= -169 : (-3)= 56,33[tex]~[/tex][tex]__________________________________________________________________________________________[/tex][tex] \\ \\ [/tex] [tex]\blue{\boxed{\colorbox{skyblue}{\rm{- AvR}}}}[/tex]

Answered by JcyntAvrWiguna | 2025-07-04

[tex] - 13 \times 13 \div ( - 3) \\ = - 169 \div ( - 3) \\ = 56.333[/tex]

Answered by aquila0152 | 2025-07-04