c\\a+c > b\\b+c > c\\\\if\ a\leq b\leq c\ then\ a+b > c\\------------------------\\a=6;\ b=9\to a+b=6+9=15\ then\ c=10\ or\ c=12\\\\a=6;\ c=9\to b=4\ because\ a+b=6+4=10 > 9\\a=6;\ c=9\to b=7\ because\ a+b=6+7=15 > 9\\\\Answer:A.10;\ B.7;\ C.4;\ F.12"> a , b , c − l e n g t h s s i d es o f a t r ian g l e , t h e n : a + b > c a + c > b b + c > c i f a ≤ b ≤ c t h e n a + b > c − − − − − − − − − − − − − − − − − − − − − − − − a = 6 ; b = 9 → a + b = 6 + 9 = 15 t h e n c = 10 or c = 12 a = 6 ; c = 9 → b = 4 b ec a u se a + b = 6 + 4 = 10 > 9 a = 6 ; c = 9 → b = 7 b ec a u se a + b = 6 + 7 = 15 > 9 A n s w er : A .10 ; B .7 ; C .4 ; F .12
The lengths of the third side of the triangle can be 10, 7, 4, or 12. The lengths that do not work are 2 and 15. Thus, the valid options are A, B, C, and F.
;
Faktorisasi prima6 = 2 × 310 = 2 × 5A. Berenang setiap berapa hariKPK= 2 × 3 × 5= 6 × 5= 30 hariB. Berenang untuk pertama kalinya= 2 × 30 ÷ 7= 60 ÷ 7= 8 sisa 4 hari= 4 hari sebelum sabtu= Selasa[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]