a) First we calculate the volume of each ball:
V = 3 4 π r 3 V = 3 4 ∗ ( 3 , 14 ) ∗ ( 1.25 ) 3 = 8 , 177 s q u a re in c h
b) Now we calculate the volume of tree balls:
V T = 3 ∗ 8 , 177 = 24.531 s q u a re in c h
c) Now we calculate the volume of cylinder:
c1) Base area:
A b = π r 2 A b = 3 , 14 ∗ ( 1 , 25 ) 2 = 4.906 s q u a re in c h
c2) Cylinder height
h = 3 ∗ ( 2.5 ) = 7.5 in c h
c3) Cylinder Volume:
V C = A b ∗ h V C = 4.906 ∗ 7.5 = 36.795 c u bi c in c h
d) Finally we calculate the internal space:
s = 36.795 − 24.531 = 12 , 264 c u bi c in c h
d = 2.5 in r = 2 d = 2 2.5 = 1.25 in π = 3.14 V o l u m e o f a C y l in d er : V = π r 2 h
h = 3 ⋅ d = 3 ∗ 2.5 = 7.5 in V c = 3.14 ⋅ ( 1.25 ) 2 ⋅ 7.5 = 23.55 ∗ 1.5625 = 36.80 i n 3
T h e v o l u m e o f t ree ba ll s : V 3 b = 3 ⋅ 3 4 π r 3 = 4 π r 3 V 3 b = 4 ⋅ 3.14 ⋅ ( 1.25 ) 3 = 12.56 ⋅ 1.9531 ≈ 24.53 i n 3 V c − V 3 b = 36.80 − 24.53 = 12.27 i n 3 A n s w er : T h e v o l u m e n o t occ u p i e d b y ba ll s i t 12.27 i n 3
The volume of space in the can not occupied by the three tennis balls is approximately 12.29 cubic inches. This calculation involves finding the volume of both the cylinder can and the total volume of the spheres (tennis balls) within it. After computing both volumes, the empty space is found by subtracting the volume of the tennis balls from the volume of the can.
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Jawaban:Jika x = 5 dan y = 2, maka:x - 2y = 5 - 2 * 2 = 5 - 4 = 1Namun, tanpa nilai-nilai tersebut, jawabannya tetap x - 2y.