cermin cekung berjari jari 100 cm,didepannya diletakkan benda berjarak 60 cm.Tentukan jarak bayangan yang terbentuk,lukis bayangan yang terbentuk dan sifat bayangan benda yang terbentuk

2 x 2 − 2 x − 12 = 0 2 x 2 + 4 x − 6 x − 12 = 0 2 x ( x + 2 ) − 6 ( x + 2 ) = 0 ( x + 2 ) ( 2 x − 6 ) = 0 ⟺ x + 2 = 0 ∨ 2 x − 6 = 0 x = − 2 ∨ x = 3

Answered by Anonymous | 2024-06-10

2 x 2 − 2 x − 12 = 0 2 ( x 2 − x − 6 ) = 0 2 ( x 2 − 3 x + 2 x − 6 ) = 0 2 ( x ( x − 3 ) + 2 ( x − 3 )) = 0 2 ( x + 2 ) ( x − 3 ) = 0 x = − 2 ∨ x = 3

Answered by konrad509 | 2024-06-10

To solve the quadratic equation 2 x 2 − 2 x − 12 = 0 by factoring, first factor out the common factor of 2 and simplify to x 2 − x − 6 = 0 . This expression factors to ( x − 3 ) ( x + 2 ) = 0 , yielding the solutions x = 3 and x = − 2 .
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Answered by Anonymous | 2024-09-27

Jawaban:Penjelasan:Diketahui:[tex]M=100\text {cm}\\s_o=60\text {cm}\\[/tex]Ditanyakan:[tex]s_i=?[/tex]Alternatif penyelesaian:[tex]f=\frac{M}{2} \\f=\frac{100\text{cm}}{2} \\f=50\text{cm}[/tex][tex]\frac{1}{f} =\frac{1}{s_o} +\frac{1}{s_i} \\\frac{1}{50\text{cm}} =\frac{1}{60\text{cm}} +\frac{1}{s_i} \\\frac{1}{s_i} =\frac{1}{50\text{cm}} -\frac{1}{60\text{cm}}\\\frac{1}{s_i} =\frac{6-5}{300\text{cm}} \\\frac{1}{s_i} =\frac{1}{300\text{cm}}\\s_i=300\text {cm}[/tex]Jadi jarak bayangan terbentuk pada jarak 300cm dan  karena jarak bayangan positif maka bayangan bersifat nyata.

Answered by mastreeada | 2025-07-05