All the busy-work is on the left side.
1). Take care of the (x+1)² . . .
(x + 1)² = x² + 2x + 1
2). Take care of the (x-1)² . . .
(x - 1)² = x² - 2x + 1
The problem says that (the first expression) minus (the second expression) is 32 .
(x² + 2x + 1) - (x² - 2x + 1) = 32
Can you handle this ? Only one more touchy point to take care of . . . removing the second parentheses. Since there's a negative sign before it, that changes the sign of everything inside:
(x² + 2x + 1) PLUS (- x² + 2x - 1) = 32
Now you can just erase all the parentheses:
x² + 2x + 1 - x² + 2x - 1 = 32
Now I'm just going to write the things on the left side in a different order, without changing anything:
x² - x² + 2x + 2x + 1 - 1 = 32
Isn't that neat ? ! ? What you have now is:
4x = 32
Divide each side by 4 :
x = 8
Just watch how slick that works:
(x + 1)² - (x - 1)² = ?
(x + 1) = 9 (x - 1) = 7
(9)² - (7)² = 81 - 49 = . . . . . . . . 32 !
спасибо Удачи
( x + 1 ) 2 − ( x − 1 ) 2 = 32 x 2 + 2 x + 1 − ( x 2 − 2 x + 1 ) = 32 x 2 + 2 x + 1 − x 2 + 2 x − 1 = 32 4 x = 32 / : 4 x = 4 32 x = 8
To find the value of x , start by isolating it using arithmetic operations. For example, in the equation 2 x + 4 = 12 , subtract 4 from both sides and then divide by 2 to find x = 4 . For quadratic equations, factorization or the quadratic formula can be used for solutions.
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semoga jawaban ini membantu. jangan lupa berikan ☆5 dan jadikan yang terbaik yaa ♡