Om rizal menabung di bank Rp. 2500000,00. Setiap 2 minggunya rizal mendapatkan bunga sebesar 1,5%. Jika om rizal telah menabung selama 3 bulan, berapaka total tabungan om rizal sekarang

y = 3 x − 6 ( 0 , .... ) , x = 0 y = 3 ⋅ 0 − 6 = − 6 ( 0 , − 6 )
( .... , 0 ) , y = 0 0 = 3 x − 6 3 x = 6 / : 3 x = 2 ( 2 , 0 )
( 1 , .... ) , x = 1 y = 3 ⋅ 1 − 6 = 3 − 6 = − 3 ( 0 , − 3 )

Answered by Lilith | 2024-06-10

The ordered pairs for the equation y = 3 x − 6 are ( 0 , − 6 ) , ( 2 , 0 ) , and ( 1 , − 3 ) . Each value is found by substituting the given x or y into the equation. By solving, we can complete the pairs accurately.
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Answered by Lilith | 2024-12-24

Jawaban:Rp. 15.225.000Penjelasan:Rizal menabung setiap 2 Minggu1 bulan = 4 Minggu3 bulan = 12 Minggu12 Minggu : 2 Minggu = 6jadi pak Rizal dalam 3 bulan menabung 6 kalijadi penyelesaiannya:2.500.000 × 6 = 15.000.000bunganya: 1,5/100 ×2.500.000 = 37.50037.500 × 6 = 225.000jadi, total tabungan pak Rizal adalah:15.000.000 + 225.000 = 15.225.000

Answered by icekingwanderer | 2025-07-04