Hallo, bantu jawab buat yang masih aktif. Soal pecahan1.) 25% + ¾ - ⅛ × ⅘2.) ⅞ ÷ ⅚ × ⅐ - 3½ . Thanks, kalau bisa tanpa AI. Bangga lah pakai usaha sendiri-! Pagi, hehe.
Answer (3)
width = 5x length = 7x
Perimeter = 10x + 14x = 24x = 96cm x = 96/24 = 4cm
width = 5x = 20cm length = 7x = 28cm
Area = (20cm x 28cm) = 560 cm²
The area of the rectangle, with sides in the ratio 5:7 and a perimeter of 96 cm, is 560 cm². This is calculated by first determining the dimensions based on the ratio and then using them to find the area. The width is 20 cm and the length is 28 cm.
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Penjelasan dengan langkah-langkah:Question : 1[tex]\tt{}25\% + \frac{3}{4} - \frac{1}{8} \times \frac{4}{5} [/tex][tex]\tt{} = \frac{25}{100} + \frac{3}{4} - \frac{1}{8} \times \frac{4}{5} [/tex][tex] \tt{} = \frac{25}{100} + \frac{3}{4} - \frac{1}{2} \times \frac{1}{5} [/tex][tex]\tt{} = \frac{25}{100} + \frac{3}{4} - \frac{1}{10} [/tex][tex]\tt{} = \frac{5}{25} + \frac{3}{4} - \frac{1}{10} [/tex][tex]\tt{} = \frac{5 \times 1}{20 \times 1} + \frac{3 \times 5}{4 \times 5} - \frac{1 \times 2}{10 \times 2} [/tex][tex]\tt{} \frac{5}{20} + \frac{15}{20} - \frac{2}{20} [/tex][tex]\tt{} = \frac{18}{20} = \frac{9}{10} \\ [/tex]Question : 2[tex]\tt{} \frac{7}{8} \div \frac{5}{6} \times \frac{1}{7} - 3 \frac{1}{2} [/tex][tex]\tt{} = \frac{7}{8} \div \frac{5}{6} \times \frac{1}{7} - \frac{7}{2} [/tex][tex]\tt{} = \frac{7}{8} \times \frac{6}{5} \times \frac{1}{7} - \frac{7}{2} [/tex][tex]\tt{} = \frac{1}{4} \times \frac{3}{5} - \frac{7}{2} [/tex][tex]\tt{} = \frac{1 \times 3}{4 \times 5} - \frac{7}{2} [/tex][tex]\tt{} = \frac{3}{20} - \frac{7}{2} [/tex][tex]\tt{} = \frac{3}{20} - \frac{7 \times 10}{2 \times 10} [/tex][tex]\tt{} = \frac{3}{20} - \frac{70}{20} [/tex][tex]\tt{} = \frac{3 - 70}{20} [/tex][tex]\tt{} = - \frac{67}{20} = - 3 \frac{7}{20} [/tex]
