Sebuah solenoida panjang memiliki 500 lilitan dengan panjang 0,5 m. Jika arus listrik sebesar 2 A mengalir melalui solenoida, tentukan besar medan magnet di dalam solenoida. Gunakan: B = μ。x (N/L) x 1 Ho=4π × 10-7 T·m/A A. 2,51 x 10-3 T B. 3,14 x 10-3 T C. 5,03 × 10-3 T D. 6,28 × 10-3 T​

1470∣2 .735∣5 .147∣3 . 49∣7 . 7∣7 . 1∣ 1470 = 2 × 5 × 3 × 7 2 = 30 × 49 S o l u t i o n : t hi s a n u mb er e q u a l 30 , b ec a u se 1470 : 30 = 49 = 7 2

Answered by Anonymous | 2024-06-10

The least number by which 1470 must be divided to obtain a perfect square is 30. This is determined by ensuring that all prime factors of 1470 have even exponents after division. Dividing 1470 by 30 results in 49, which is a perfect square (7²).
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Answered by Anonymous | 2024-10-02

Jawaban:A. 2,51 × 10⁻³ TPenjelasan:Untuk solenoida tanpa inti (inti udara atau vakum) dengan panjang L dan jumlah lilitan N, kuat/besar medan magnet di tengah-tengah solenoida dapat dicari menggunakan persamaan:[tex]\displaystyle B = \mu_0 nI, \qquad n=\frac{N}{L}[/tex]∴ Kuat B di dalam solenoida pada soal adalah:[tex]\begin{aligned}B = \mu_0 nI &= \frac{\mu_0 NI}{L}\\&= \frac{\left(4\pi \times 10^{-7} \text{ T}\cdot \text{m}\right)\left(500\right)\left(2 \text{ A}\right)}{0{,}5\text{ m}}\\&= 8\pi \times 10^{-4} \text{ T} \approx \boxed{2,51\times 10^{-3} \text{ T}}\end{aligned}[/tex]Maaf kalau salah, semoga cukup membantu.

Answered by AbdullahAlFaqir | 2025-07-06

Jawaban:penjelasan akuntansi keuangan

Answered by kandasileme | 2025-07-06