Eq u a t i o n o f c i rc l e r 2 = ( x − a ) 2 + ( y − b ) 2 a , b − coor d ina t es o f ce n t er o f c i rc l e ( a , b ) = ( − 1 , − 3 ) r 2 = ( x + 1 ) 2 + ( y + 3 ) 2 S u b s t i t u t in g p o in t ( 3 , 0 ) r 2 = ( 3 + 1 ) 2 + ( 0 + 3 ) 2 r 2 = 4 2 + 3 2 r 2 = 16 + 9 = 25 r = 5 A n s w er : 25 = ( x + 1 ) 2 + ( y + 3 ) 2
The standard equation of the circle with center (-1, -3) that passes through the point (3, 0) is ( x + 1 ) 2 + ( y + 3 ) 2 = 25 . We found this by using the center coordinates to form the equation and then calculating the radius from the point on the circle.
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