Pak hasan mempunyai tanah berbentuk persegi panjang dengan P = 14m dan L = 5m. Jika pak hasan menjual tanah dengan harga 500000 per meter makah total harga tanah pak hasan adalah
Answer (4)
Genera\ equation\ for\ line\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (-2,3),\ (4,-1)\ into\ equation\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {-1=4a+b\ |*-1}} \right.\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {1=-4a-b\}} \right.\\+----\\\\Addition\ method\\\\4=-6a\ \ |:-6\\\\a=-\frac{4}{6}=-\frac{2}{3}\\\\b=3+2a=3+2* (-\frac{2}{3})=3-\frac{4}{3}=1\frac{2}{3}\\\\y=-\frac{2}{3}x+1\frac{2}{3}
The equation of the line that passes through the points (-2, 3) and (4, -1) is y = − 3 2 x + 3 5 . This is derived using the point-slope formula to calculate the slope and then rearranging to find the slope-intercept form. The slope is − 3 2 and the y-intercept is 3 5 .
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Jawaban:35.000.000Penjelasan dengan langkah-langkah:= p × l × harga= 14 m × 5 m × 500.000/m²= 70 m² × 500.000/m²= 35.000.000[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]
DiketahuiPanjang 14 mLebar 5 mMenjual Rp 500.000 Per meterDitanyaTotal harga pak hasanDijawabLuas[tex] = p \times l \\ = 14 \times 5 \\ = 70[/tex]Harga[tex] = 70 \times 500.000 \\ = 35.000.000[/tex]KesimpulanMaka harganya Rp 35.000.000
