sebutkan 25 nabi palsu

0\ and\ x+1>0\\x>0\ and\ x>-1\\\\ (x+x+1)(x+1-x)+8=x^2+(x+1)^2\\\\(2x+1)*1+8=x^2+x^2+2x+1\\\\2x+1+8=2x^2+2x+1\\\\-2x^2+2x-2x=1-8-1\\\\-2x^2=-8\ \ |:(-2)\\\\x^2=4\\\\x=2\ \ or\ \ x=-2\ -\ reject\ conditions\ are\ not\ satisfied\\\\Two\ consecutive\ numbers\ are:\ 2\ and\ 3."> x , x + 1 − tw o co n sec u t i v e n u mb ers C o n d i t i o n : x > 0 an d x + 1 > 0 x > 0 an d x > − 1 ( x + x + 1 ) ( x + 1 − x ) + 8 = x 2 + ( x + 1 ) 2 ( 2 x + 1 ) ∗ 1 + 8 = x 2 + x 2 + 2 x + 1 2 x + 1 + 8 = 2 x 2 + 2 x + 1 − 2 x 2 + 2 x − 2 x = 1 − 8 − 1 − 2 x 2 = − 8 ∣ : ( − 2 ) x 2 = 4 x = 2 or x = − 2 − re j ec t co n d i t i o n s a re n o t s a t i s f i e d Tw o co n sec u t i v e n u mb ers a re : 2 an d 3.

Answered by luana | 2024-06-10

The two consecutive positive numbers that meet the criteria are 2 and 3. By defining the two numbers as x and x + 1, setting up an equation based on their sum and difference, and solving for x, we arrived at these values. The conditions of the problem were effectively transformed into a quadratic equation leading us to the correct solution.
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Answered by luana | 2024-12-24

JawabMusailamah al-KazzabAl-Aswad al-‘AnsiTulayhah bin KhuwailidSajah binti Al-HaritsMirza Ghulam AhmadRashad KhalifaElijah MuhammadBahá'u'lláhMirza Ali Muhammad (Bab)Abu Manshur al-IjliAhmed al-HassanHassan Farhan al-MalikiAli Muhammad bin WaliIsa Langkat (Indonesia)Lia Eden (Lia Aminuddin)Ahmad Mushaddeq (Indonesia)Joseph Smith (pendiri Mormon)Father DivineSun Myung Moon (Unification Church)David KoreshSerigne Touba (disebut nabi oleh sebagian pengikut ekstrem)Muhammad bin TumartMansur Al-Hallaj (disebut nabi oleh pengikut tertentu, meskipun dia sufi)George Baker (Father Divine)Al-Harith al-Kadhdhab

Answered by sosokhytam1337 | 2025-07-10