Reduksi besi(III) oksida dengan CO menghasilkan besi menurut persamaan reaksi: Fe2O3 + 3CO → 2Fe +3CO2. Untuk menghasilkan 11,2 kg besi (Ar Fe=56) dibutuhkan besi(III) oksida sebanyak

Let length = l , width = b Perimeter = 2 (l +b) 46= 2 (l +b) (l + b) = 23
l*b = 120
So l + 120/l = 23 l^2 + 120 - 23l = 0 l^2 -15l + 8l + 120 = 0 (l-8) (l - 15) = l = 8 or 15 i.e if l =8, w=15 and if l = 15, w = 8

Answered by Pulkit | 2024-06-10

We found the dimensions of the rectangle by setting up equations for perimeter and area. Solving the resulting quadratic equation gave us the width and length as 8 cm and 15 cm. Thus, the rectangle's dimensions are 8 cm by 15 cm.
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Answered by Anonymous | 2024-12-24

Jawaban:Berikut langkah-langkah untuk menghitung banyaknya besi(III) oksida yang dibutuhkan: 1. Tentukan mol besi (Fe): - Massa besi (Fe) = 11,2 kg = 11200 gram- Ar Fe = 56 g/mol- Mol Fe = massa Fe / Ar Fe = 11200 g / 56 g/mol = 200 mol 2. Tentukan mol besi(III) oksida (Fe₂O₃) berdasarkan perbandingan stoikiometri: - Dari persamaan reaksi: 1 mol Fe₂O₃ menghasilkan 2 mol Fe- Jadi, mol Fe₂O₃ = (mol Fe / 2) = 200 mol / 2 = 100 mol 3. Tentukan massa besi(III) oksida (Fe₂O₃): - Mr Fe₂O₃ = (2 x Ar Fe) + (3 x Ar O) = (2 x 56) + (3 x 16) = 112 + 48 = 160 g/mol- Massa Fe₂O₃ = mol Fe₂O₃ x Mr Fe₂O₃ = 100 mol x 160 g/mol = 16000 gram = 16 kg Jadi, dibutuhkan 16 kg besi(III) oksida untuk menghasilkan 11,2 kg besi.

Answered by agusirary | 2025-07-07