Hutan lindung yg ada di jambi
Answer (3)
y=ax+b
we put this points into general formula { 8 = 6 a + b − 1 = a ∗ 0 + b b = − 1 8 = 6 a − 1 6 a = 9 a = 2 3 y = 2 3 x − 1
{ 7 = 9 a + b 1 = 3 a + b b = 1 − 3 a 7 = 9 a + 1 − 3 a 6 a = 6 a = 1 b = 1 − 3 ∗ 1 = − 2 y = x − 2
{ 14 = 10 a + b 2 = a + b b = 2 − a 14 = 10 a + 2 − a 12 = 9 a a = 3 4 b = 2 − 3 4 = 3 2 y = 3 4 a + 3 2
{ 5 = − 3 a + b 0 = b 5 = − 3 a a = − 3 5 y = − 3 5 a
To find the equation of a line through two points, calculate the slope a and y-intercept b . The equations derived for the given points are: 1) y = 2 3 x − 1 , 2) y = x − 2 , 3) y = 3 4 x + 3 2 , and 4) y = − 3 5 x . These equations represent the lines passing through the specified points.
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Jawaban:hutan lindung Bukit Limau , TNBT, taman nasional bukit dua belas, hutan Penelitian, kebun raya bukit sariPenjelasan:semoga membantu
