Negara mata uang wu jiao
Answer (4)
Perimeter of the rectangle is 2*(80+125)=410 The rectangle having the biggest area given the same perimeter is a square. So we need to go "the other way" -- find the rectangle with larger side ratio. 200 m and 5 m is a good example.
The area of the first rectangle: 80 m × 125 m = 10000 m 2 The area of the second rectangle : 200 m × 5 m = 1000 m 2 (10 times smaller).
To calculate the length and width of another rectangular field that has the same perimeter but a smaller area than the original field that is 80 meters wide and 125 meters long, first, we determine the perimeter of the original field.
The perimeter (P) of a rectangle is given by the formula P = 2 × length + 2 × width. For the original field, P = 2 × 125 + 2 × 80 = 250 + 160 = 410 meters.
To find another rectangular field with the same perimeter but a smaller area, we need dimensions such that the product of the length and width is less than the product of the original field's length and width (which is 125 × 80 = 10000 square meters).
Let's say the new field has a width of 90 meters. The new length would be calculated as follows:
P = 2 × new length + 2 × 90 410 = 2 × new length + 180 new length = (410 - 180) / 2 new length = 230 / 2 new length = 115 meters
The new dimensions give us a field 90 meters wide and 115 meters long. The area of this field is 90 × 115 = 10350 square meters, which is smaller than the area of the original field.
To find a rectangle with the same perimeter of 410 meters but a smaller area, we calculated areas of different length and width combinations. For example, a rectangle measuring 195 meters long and 10 meters wide has an area of 1950 square meters, which is smaller than the original area. Another rectangle could measure 185 meters long and 20 meters wide with an area of 3700 square meters.
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china (Tiongkok)penjelasan:Wu” (五) = 5“Jiao” (角) = 1/10 dari 1 yuan (seperti "sen" dalam rupiah)
