Travalaho Fisika 1. Um liquido flui através de um tubo de secção transversal constante igual a 5 m² com velocidade de 100 m/s, determine: a. O caudal volumétrico do liquido ao longo do tubo b. O volume de liquido que atravessa uma secção de 10 s.
Answer (4)
yes because its a whole number
Answer with explanation:
→A number is said to be rational number , if it can be written in the form of
q p , where q≠0.
→A rational number is said to be terminating decimal if denominator of rational number is in the form of
2 m or 5 n or 2 m × 5 n
otherwise , it is non terminating repeating decimal.
→The given Rational number is
3 13
Here denominator contains neither powers of 2 , nor powers of 5, nor power of 2 × 5, so it is a non terminating repeating decimal , still a rational number.
The decimal form of 3 13 , which equals 4.333... , is a rational number. A rational number is defined as any number that can be expressed as a fraction of two integers. Since 3 13 fits this definition, it is rational.
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Jawaban:Untuk menyelesaikan soal ini, kita gunakan konsep **debit volumetrik** dan **volume aliran**.---### Diketahui:* Luas penampang pipa: [tex]$A = 5 \, \text{m}^2$[/tex]* Kecepatan aliran: [tex]$v = 100 \, \text{m/s}$[/tex]* Waktu: [tex]$t = 10 \, \text{s}$[/tex]---### a. Debit Volumetrik[tex]($Q$)[/tex]Rumus debit volumetrik:[tex]$$Q = A \times v$$[/tex]Substitusi nilai:[tex]$$Q = 5 \, \text{m}^2 \times 100 \, \text{m/s} = 500 \, \text{m}^3/\text{s}$$[/tex]✅ **Jawaban a**: Debit volumetrik = **500 m³/s**---### b. Volume Cairan dalam 10 detikRumus volume aliran:[tex]$$V = Q \times t$$[/tex]Substitusi nilai:[tex]$$V = 500 \, \text{m}^3/\text{s} \times 10 \, \text{s} = 5000 \, \text{m}^3$$[/tex]✅ **Jawaban b**: Volume cairan = **5000 m³**
