1. Tetapan kesetimbangan: CO + H2O → CO2 + H2 adalah 0,1. Berapa jumlah mol CO yang harus dicampurkan pada 7 mol H2O dalam volume (no mhs masing masing dijid terakhir) liter agar menghasilkan 3 mol H2. (Nim terakhir saya 13)2. 2. Dari reaksi 2HI H2 + 12 mempunyai harga kesetimbangan 1/3. Berapa mol H2 yang dihasilkan bila mula-mula ada 9 mol Hi pada volume 5 liter.​

you must add all together 60. 43 .

Answered by mp85 | 2024-06-10

The** total cost will be estimated by adding cost of all the items i.e., $ 60.43 .**
It is given that **Leo **bought **items , **cost of which are ; **shoes **cost 19.99 , ∗ ∗ soc k s ∗ ∗ cos t 4.19, shirt costs $ 8.50 and pants cost $27.75.
We have to find how can he estimate the** total cost ?**
What is algebra ?
Algebra is the** branch of mathematics **that deals with various symbols and the arithmetic operations such as addition , multiplication , etc.
As per the question ;
Cost of shoe = **$ 19.99 **
Cost of sock = $ 4.19
Cost of shirt =** $8.50 **
Cost of **pant **= $ 27.75
**Total cost **can be calculated by adding cost of all the above items ;
= 19.99 + 4.19 + 8.50 + 27.75
= **$ 60.43 **
Thus, the **total cost **will be **estimated **by adding cost of all the items i.e., $ 60.43 .
To learn more about algebra click here :
https://brainly.com/question/19253676
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Answered by psm22415 | 2024-06-16

To estimate the total cost of Theo's items, round each price to the nearest whole number and add them together. The estimated total cost would be about $61.00. This method provides a quick way to approximate expenses.
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Answered by psm22415 | 2025-02-11

1. Reaksi: CO + H2O <=> CO2 + H2
- Diketahui:
K = 0,1
H2O = 7 mol
Volume = 3 liter (dari NIM berakhir 13)
H2 setimbang = 3 mol
ICE Table:
CO + H2O <=> CO2 + H2
x mol 7 mol 0 mol 0 mol
-3 -3 +3 +3
x-3 4 3 3
K = [CO2][H2] / [CO][H2O]
= (1)(1) / ((x-3)/3)(4/3) = 0,1
-> 0,1 = 9 / 4(x - 3)
-> x - 3 = 22,5 -> x = 25,5
Jawaban 1: Jumlah mol CO yang harus dicampurkan adalah 25,5 mol
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2. Reaksi: 2HI <=> H2 + I2
- Diketahui:
K = 1/3Hl = 9 mol
Volume = 5 liter
ICE Table:
2HI <=> H2 + I2
9 mol 0 mol 0 mol
-2x +x +x
9-2x x x
K = [H2][I2] / [HI]^2
= (x/5)^2 / ((9-2x)/5)^2 = x^2 / (9 - 2x)^2 = 1/3
-> x^2 = (9 - 2x)^2 / 3
-> 3x^2 = 81 - 36x + 4x^2
-> x^2 - 36x + 81 = 0
-> x = 18 +/- 3sqrt27 ~ 18 +/- 15,6
-> x ~ 2,4 mol
Jawaban 2: Mol H2 yang dihasilkan adalah 2,4 mol

Answered by andreskris62p6au2s | 2025-07-10