Sebuah benda mengalami gerak harmonik sederhana dengan
persamaan simpangan y = 0,4sin(ωt). Simpangan y dalam satuan
meter (m) dan t dalam detik (s). Diketahui frekuensi gerak
harmonik benda adalah 1/8 Hertz. Berapakah kecepatan gerak
harmonik benda saat simpangannya 0,2 m?

9605.3 since 2 is lower than five you keep it the same.

Answered by itsdakork | 2024-06-10

9605.327 rounded to the nearest ten is 9610. ;

Answered by BenicioDelToro | 2024-06-18

When rounding 9605.327 to the nearest ten, the tens place is 6. The digit to the right is 0, which means we do not round up, resulting in 9600.
;

Answered by itsdakork | 2025-01-23

jawabannya ya kak, semoga paham

Answered by lrntrn17 | 2025-07-17