100celcius ramor adalah pelajaran
Answer (3)
2 m 2 − 7 m − 3 = 0 a = 2 ; b = − 7 ; c = − 3 Δ = b 2 − 4 a c → Δ = ( − 7 ) 2 − 4 ⋅ 2 ⋅ ( − 3 ) = 49 + 24 = 73 x = 2 a − b ± Δ → x = 2 ⋅ 2 7 ± 73 = 4 7 ± 73
4 b 2 + 8 b + 7 = 4 4 b 2 + 8 b + 7 − 4 = 0 4 b 2 + 8 b + 3 = 0 4 b 2 + 2 b + 6 b + 3 = 0 2 b ( 2 b + 1 ) + 3 ( 2 b + 1 ) = 0 ( 2 b + 1 ) ( 2 b + 3 ) = 0 ⟺ 2 b + 1 = 0 or 2 b + 3 = 0 2 b = − 1 or 2 b = − 3 b = − 2 1 or b = − 2 3
5 80 a 2 = 5 80 ⋅ a 2 = 5 16 ⋅ 5 ⋅ ∣ a ∣ = 5 ⋅ 16 ⋅ 5 ⋅ ∣ a ∣ = 5 ⋅ 4 ⋅ 5 ⋅ ∣ a ∣ = 20∣ a ∣ 5
− 6 150 r = − 6 25 ⋅ 6 r = − 6 25 ⋅ 6 r = − 6 ⋅ 5 6 r = − 30 6 r
3 2 = 3 2 ⋅ 3 3 = 3 2 3
5 3 6 = 5 1 ⋅ 3 6 = 5 1 3 6 = 5 1 2 = 5 2
To solve the first two equations, use the quadratic formula and factorization. The simplifications involve extracting square roots and rationalizing denominators. Each step follows algebraic rules to arrive at simplified forms or solutions.
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mata pelajaran fisika bab 7
