27 = 3 c − 3 ( 6 − 2 c ) 27 = 3 c − 18 + 6 c 3 c + 6 c = 27 + 18 9 c = 45 c = 9 45 c = 5 A n s w er
The **equivalent **value of the **equation **is c = 5
Given data ,
Let the **equation **be represented as A
Now , the value of A is
27 = 3c - 3 ( 6 - 2c )
On using the **distributive **property , we get
27 = 3c - 3 ( 6 ) + 3 ( 2c )
27 = 3c - 18 + 6c
Grouping the like terms in the **expression **, we get
27 = 9c - 18
Divide by 9 on both sides , we get
3 = c - 2
Adding 2 on both sides , we get
c = 3 + 2
On simplifying the **equation **, we get
c = 5
Hence , the **expression **is c = 5
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To solve the equation 27 = 3 c − 3 ( 6 − 2 c ) , we simplify using the distributive property and combine like terms, leading to c = 5 .
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