if AE is x+50, then the whole thing must be x=50. if a portion of that, CE, is x+32, then the rest of it, AC, must be x+18. Because no matter what X is, 32+18=50.
Answer:
** AC= 18**
Step-by-step explanation:
It is given that:
Points A,B,C,D, and E are collinear and in that order.
AE = x+50 and CE = x+32.
Now, we know that the length of the line segment AC is equal to the length of the line segment AE minus the length of the line segment CE.
i.e.
AC=AE-CE
i.e.
AC= x+50-(x+32)
AC=x+50-x-32
( Since if the sign before the parentheses is negative then the terms comes out of the parentheses with a opposite sign )
Hence, on combining the like terms we have:
AC=x-x+50-32
AC=0+18
Hence, we get:
** AC= 18**
The length of segment AC is found to be 18 units by subtracting the lengths of segments CE from AE. This is derived using the equations provided for AE and CE. The final answer is A C = 18 units.
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