basic line equation is y = mx+b for this question you have to isolate y so: 4x -5y = 5 4x - 5 = 5y 4/5x -1 = y (divided left side by 5) so slope is 4/5 and y intercept is -1
The slope and y-intercept of the line represented by 4x - 5y = 5, we rewrite it in the slope-intercept form y = mx + b. The slope is 4/5, and the y-intercept is -1.
To find the slope and y-intercept of the linear equation 4x - 5y = 5, we need to solve for y in terms of x to get it into slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.
Here are the steps to solve for y:
4x - 5y = 5
Subtract 4x from both sides: -5y = -4x + 5
Divide both sides by -5 to solve for y: y = (4/5)x - 1
From this, we can see that the slope (m) is 4/5 and the y-intercept (b) is -1.
The slope of the equation 4 x − 5 y = 5 is 5 4 and the y-intercept is -1. This is derived by rewriting the equation in slope-intercept form. The resulting line crosses the y-axis at (0, -1).
;
Jawaban:kalau kurang jelas bisa tanya di komentar