Jika dalam peta tertulis skala 1 banding 350.000 maka setiap 1 cm pada jarak adalah

Grant, he pays 10 cents in every additional minute he used in long distance call
plus, he pays $5 per months.
Now, we need to make an algebraic expression that shows how much will Grant pay for his long distance call in a month.
=> First let’s assign a variable for minutes. Let m be the value of minutes
=> 10 cents per minute additional and 5 dollars per month
=> 10 cents (m) + 5 dollars, where m is equals to the number of minutes he will use in a month.
=> SO we will multiply 10 cents to the number of minutes he used in a month, then add the 5 dollars he pay every month.

Answered by taskmasters | 2024-06-10

To determine the algebraic expression for the cost of m minutes of long distance calls that Grant would incur in one month, we use the pricing structure provided. Since Grant pays a monthly fee of $5 plus an additional 10 cents per minute for the calls, the expression would incorporate both the fixed monthly fee and the variable cost per minute.
The cost per minute is 10 cents, or $0.10, and this is multiplied by the number of minutes (m). Therefore, the variable cost for m minutes is $0.10m. Next, we add the fixed monthly fee of $5 to this variable cost to get the total cost for m minutes of calls.
Algebraic Expression: Total Cost = $0.10m + $5

Answered by IngridBergman | 2024-06-24

The algebraic expression for Grant's monthly long distance call charges is C = 0.10 m + 5 , where m is the number of minutes. This expression combines the cost per minute and the fixed monthly fee. Therefore, for any amount of minutes used, you can plug it into this expression to find the total cost.
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Answered by taskmasters | 2024-10-01

Jawaban:350.000 cm atau 3,5 kmPenjelasan dengan langkah-langkah:Jika pada peta tertulis skala 1 : 350.000, maka setiap 1 cm pada peta mewakili 350.000 cm atau 3,5 kilometer pada jarak sebenarnya.

Answered by Adriany | 2025-07-11