Logam aluminium direaksikan dengan larutan asam sulfat menurut reaksi : 2Al(s) + 3H2SO4(aq) Al2(SO4)3(aq) + 3H2(g). Jika massa Al2(SO4)3 yang terbentuk = 34,2 gram. Volume gas H2 yang dihasilkan pada STP adalah .... (Mr Al2(SO4)3 = 342) a.6,72 liter b.5,6 liter c.4,8 liter d.2,24 liter e.1,12 liter Mohon bantuannya..
Answer (4)
The two equivalent ratios are:
** 2:2**
** and 5:5** ;
In mathematics, a **ratio **is a relationship between two numbers that indicates how many times the first number contains the second. Put another way, a ratio says how much of one thing there is compared to another thing.
We can express ratios in different ways.
a) We Use the the symbol : to separate the values. For instance:
4:1
**b) We can use the word to. **For instance:
3 to 1
c) We can write it like a fraction. For instance:
1 4
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Since the problem establishes to write two ratios that are equivalent to **1:1. **From the Figure below there is 1 red square to 1 blue square. So, writing the new ratios we have:
First.
**2:2 **is equivalent to **1:1, **that is the ratio is also 1 red square to 1 blue square, even though there are more squares. You can see this in the Figure below.
Second.
**4:4 **is equivalent to **1:1. **As in the previous statement the ratio is also 1 red square to 1 blue square, even though there are four red squares and four blue squares as illustrated in the Figure.
To find two ratios equivalent to 1:1, you can multiply both numbers by the same value. For example, 2:2 and 3:3 are both equivalent to 1:1. These show that the relationship between the two quantities remains the same, regardless of how large both numbers are.
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Jawaban:6,72 LPenjelasan:Kita punya reaksi:[tex]\displaystyle 2\,\text{Al(s)} + 3\,\text{H}_2\text{SO}_4\text{(aq)} \rightarrow \text{Al}_2(\text{SO}_4)_3\text{(aq)} + 3\,\text{H}_2\text{(g)}[/tex]dengan jumlah Al₂(SO₄)₃ yang terbentuk adalah:[tex]\begin{aligned}n \text{ Al}_2(\text{SO}_4)_3 = \frac{m}{Mr} = \frac{34{,}2}{342} = 0{,}1 \, \text{mol}\end{aligned}[/tex]Dari persamaan reaksi, perbandingan mol Al₂(SO₄)₃ dan H₂ adalah 1 : 3. Jadi:[tex]\begin{aligned}n\text{ H}_2 = 3 \times n\text{ Al}_2(\text{SO}_4)_3 &= 3 \times 0{,}1 = 0{,}3 \, \text{mol}\end{aligned}[/tex]Pada kondisi STP, 1 mol gas memiliki volume 22,4 L.Maka, volume H₂ adalah 0,3 × 22,4 = 6,72 L.Maaf kalau salah, semoga cukup membantu.
