1. 6 c an s 3 c an s cos t 1$ 1 c an cos t 3 1 $ 6 ∗ 3 1 $ = 3 6 $ = 2$ 6 cans cost 2$ 2. 3 b o x es o f cere a l 1 b o x cos t s 0 , 99$ 3 ∗ 0 , 99$ = 2 , 97$ 3 boxes of cereal cost 2,97$. 3. 1 l o a f o f b re a d cos t 0 , 45$ 1 ∗ 0 , 45 = 0 , 45$ One loaf of bread costs 0,45$ 4. 6 l b s 2 l b s cos t 0 , 8$ 1 l b s cos t s 0 , 4$ 6 ∗ 0 , 4$ = 2 , 4$ 6 lbs of aplles cost 2,4$ 5. 1 b o x o f j e ll o 2 b o x es o f j e ll o cos t 0 , 54$ 1 b o x cos t s 2 0 , 54$ = 0 , 27$ 1 box of jello costs 0,27$.
To find the total cost of all items, we calculated the cost for each item individually. The final total comes to $7.09 after summing up all the individual costs. Each calculation was based on the specified rates for each item.
;
Jawaban:pertama, perlu disamakan reaksinya C4H8(9) + O2(g) → CO2(g) + H2O (9) C4H8 kita coba kasih koef. 1, jadinya koefisien CO2 disebelah harus 4 (kan C4 = 4C)dan H8 berarti disebelah harus 4 H2, jadi 4 H2OC4H8 + O2 -> 4 CO2 + 4H2OLalu O disebelah kanan sekarang ada 12, di kiri berarti 6 O2C4H8 + 6O2 -> 4CO2 + 4H2OPerbandingan koef. gas CO2 dan uap air = 4:4 = 1:1