diketahui laju reaksi Ne = 75 mL/jam, v awal= 0,5 mL, ditanyakan berala mL He yang tersisa (Ar Ne= 14 g/mol; He= 4g/mol
Answer (4)
x;y-the\ numbers\\\\ \left\{\begin{array}{ccc}\frac{x+y}{2}=25&|multiply\ both\ sides\ by\ 2\\x-y=8\end{array}\right\\+\left\{\begin{array}{ccc}x+y=50\\x-y=8\end{array}\right\ \ \ |add\ sides\ of\ the\ equations\\---------\\.\ \ \ \ \ \ \ \ 2x=58\ \ \ \ \ \ \ |divide\ both\ sides\ by\ 2\\.\ \ \ \ \ \ \ \ \ \ x=29\\\\29+y=50\\y=50-29\\y=21\\\\Answer:29\ and\ 21.
The numbers are 29 and 21.
Finding Two Numbers Given Average and Difference
The question involves finding two numbers when their average is known to be 25 and their difference is 8. To solve this, we use the properties of averages and the relationship between the numbers. Since the average of two numbers is simply the sum of those numbers divided by 2, we can represent the two numbers as x and y, and set up the equation (x+y)/2 = 25. To incorporate the second piece of information regarding the difference of the two numbers, we write another equation, x - y = 8.
Solving these two equations simultaneously gives us: (x+y)/2 = 25 → x + y = 50
x - y = 8
Adding these two equations, we get 2x = 58, which means x = 29. Substituting x back into one of the equations to find y gives us y = 50 - x = 50 - 29 = 21. Therefore, the two numbers are 29 and 21.
The two numbers are 29 and 21, which were derived from a system of equations based on their average and difference. By solving these equations step-by-step, we determined both values. Hence, we confirmed that their average is 25 and their difference is 8.
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Informasi yang diberikan dalam soal adalah:* **Laju reaksi Neon (Ne)** = 75 mL/jam* **Volume awal** = 0.5 mL* **Berat atom Neon (Ar Ne)** = 14 g/mol* **Berat atom Helium (Ar He)** = 4 g/molYang ditanyakan adalah berapa mL Helium (He) yang tersisa.---**Penjelasan Masalah**Masalah utama di sini adalah **kita tidak memiliki informasi yang cukup tentang Helium**. Kita tidak tahu:1. **Berapa volume awal Helium?** Volume awal 0.5 mL yang disebutkan bisa jadi adalah volume total (Neon + Helium) atau hanya volume awal Neon. Jika itu volume total, kita perlu tahu komposisi awalnya.2. **Apakah Helium ikut bereaksi?** Jika iya, berapa laju reaksinya?3. **Sudah berapa lama reaksi berlangsung?** Laju reaksi Neon diberikan dalam mL/jam, jadi kita perlu tahu durasi waktu agar bisa menghitung berapa banyak Neon yang bereaksi.Tanpa informasi-informasi ini, **kita tidak bisa menghitung berapa mL Helium yang tersisa**. Laju reaksi Neon dan berat atom kedua gas saja tidak cukup untuk menjawab pertanyaan tentang sisa Helium.---**Kesimpulan**Dengan informasi yang tersedia saat ini, **tidak mungkin untuk menghitung berapa mL Helium yang tersisa**. Kita memerlukan data tambahan mengenai Helium itu sendiri atau durasi reaksi.Apakah ada informasi lain yang bisa Anda berikan tentang reaksi ini?
