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In Fisika / Sekolah Menengah Atas | 2025-07-11

kawat filamen lampu pijar memiliki luas penampang 30 mm² dan suhu 437°c jika kawat filamen dianggap benda hitam sempurna , hitunglah radiasi kalor oleh kawat tersebut

Asked by Liadelia59601

Answer (3)

$200 because 200x3 is 600 -500 is 100 aka the remaining balance

Answered by likmonkey | 2024-06-10

Joan's balance in her savings account before it tripled was $200. After tripling, her balance became $600, and after withdrawing $500, she was left with $100.
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Answered by Anonymous | 2024-12-11

Jawaban:Penjelasan:Gunakan rumus Stefan-Boltzmann:P = σ × A × T^4Dengan:σ = 5,67 × 10^-8 W/m²K⁴A = 30 mm² = 3,0 × 10^-5 m²T = 437°C = 710 KP = (5,67 × 10^-8) × (3,0 × 10^-5) × (710)^4P ≈ 0,43 WattNB: ^ adalah pangkat jadi kalau ketemu seperti ini itu artinya pangkatcontoh : 10^-8 berarti 10 pangkat -8

Answered by yukiwidi68 | 2025-07-11