Let's just assume that you throw the ball with an initial speed of 2 m/s instead of dropping it like free falling. a=9.81 m/s^2 Vi= 2 m/s t= 3 x
we use the formula d = (Vi)(t) + (1/2)(a)(t)^2 d= (2)(3) + (1/2)(9.81)(9) d=50.145 m
After throwing the ball downward at 2.0 m/s for 3 seconds, it falls approximately 50.15 meters. This is calculated using the equations of motion considering both the initial speed and the acceleration due to gravity. The total distance fallen includes the contribution from both the initial velocity and gravitational acceleration.
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Jawaban:Swakelola tipe IIPenjelasan:Swakelola Tipe II adalah swakelola yang direncanakan oleh Kementerian/Lembaga/Perangkat Daerah dan dilaksanakan oleh Perguruan Tinggi Negeri (PTN) atau organisasi kemasyarakatan yang memiliki kompetensi di bidangnya.Karena dalam soal disebutkan Kementerian Keuangan bekerja sama dengan Perguruan Tinggi Negeri, maka masuk ke Swakelola Tipe II.