1 sen Malaysia berapa rupiah
Answer (4)
7 1 ( x + 21 ) = − 6 7 x + 21 = − 6 x + 21 = ( − 6 ) ∗ 7 x + 21 = − 42 x = − 42 − 21 x = − 63
There are several ways to do it. Here is one way:
1/7 (x + 21) = -6
Multiply each side by 7 : x + 21 = -42
Subtract 21 from each side : x = -63
To solve the equation 7 1 ( x + 21 ) = − 6 , first multiply both sides by 7 to eliminate the fraction, leading to x + 21 = − 42 . Then isolate x by subtracting 21, resulting in x = − 63 . The final answer is x = − 63 .
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Jawaban:harga uang kuno koin 1 sen bolong 4.999 Penjelasan:harga 1 sen di tukar di indonesia 15.000
