Suatu fluida dengan koefisien konveksi termal 0,01 kal/mºs°C memiliki luas penampang aliran 20 cm. Jika fluida tersebut mengalir dari dinding yang bersuhu 100°C ke dinding lainnya yang bersuhu 20°C dan kedua dinding sejajar, berapakah besarnya kalor yang dirambatkan?

Mental math means calculating the given numbers without using anything that can help you solve the problem like paper and pen, calculator, etc.
Now let’s have 81-16
=> 81 -16
=> 65
Now, let’s check if our answer is correct by adding the answer or the difference by the subtrahend.
By the way in subtraction
81 => minuend
16 => subtrahend
65 => difference
=> 65 + 16
=> 81
Our answer is correct. Hope this help.

Answered by taskmasters | 2024-06-10

we have
( 81 − 16 )
One way to use mental math is to add 4 to both 81 and 16
so
81 + 4 = 85 16 + 4 = 20 85 − 20 = 65
therefore
81 − 16 = 65
the answer is
65

Answered by calculista | 2024-06-11

To find 81 − 16 using mental math, break down 16 into 10 and 6 . Subtract 10 from 81 to get 71 , then subtract 6 from 71 to get the final answer of 65 .
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Answered by calculista | 2024-10-01

Penyelesaianh = 0,01 kal/m s°C[tex]A = 20~ cm[/tex][tex]T_1 = 100^\circ C[/tex][tex]T_2 = 20^\circ C[/tex][tex]20 ~cm^2 = 20 \times 10^{-4} ~m^2[/tex][tex]= 2 \times 10^{-3}~m^2[/tex][tex]Q = h \cdot A \cdot \Delta T \cdot t[/tex][tex]\dot{Q} = h \cdot A \cdot \Delta T[/tex][tex]\Delta T = T_1 - T_2[/tex][tex]= 100^\circ C - 20^\circ C[/tex][tex]= 80^\circ C[/tex][tex]\dot{Q} = h \cdot A \cdot \Delta T[/tex][tex]= 0,01 ~\text{kal}/(\text{m}^2 \cdot \text{s} \cdot ^\circ C) \times 2 \times 10^{-3} ~\text{m}^2 \times 80^\circ C[/tex][tex]= 0,01 \times 2 \times 10^{-3} \times 80[/tex][tex]= 0,01 \times 0,16[/tex][tex]= 0,0016[/tex]besar kalor = 0,0016 kal/s (kalori per detik)

Answered by vinganzbeut | 2025-07-15