bantu jawab dong kak teka teki ini, 1.snack bulu tangkis, 2.usus hitam upacara, 3.papan berpasir

let's call the digits a and b, a is ones, b is tens the number will look something like: aba,aba the sum of all the digits is 20 a + b + a + a + b + a = 20 4a + 2b = 20 2a + b = 20
b is 5 more than a b = a + 5
2a + (a + 5) = 20 (because b=a+5) 3a + 5 = 20 3a = 15 a = 5
then go back to one of our equations from before to find b: a + b + a + a + b + a = 20 5 + b + 5 + 5 + b + 5 = 20 b + b = 0 2b = 0 b = 0
therefore the number is 505,505

Answered by Anonymous | 2024-06-10

The number consists of the digits 4 and 9, repeating in the format 494, 494. The sum of the digits equals 20, and the ones digit is 5 more than the tens digit. Therefore, the number is 494, 494.
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Answered by Anonymous | 2024-10-02

Jawaban:1. Ceker ayam (snack bulu tangkis) 2. Usus hitam = Kematian (upacara) 3. Papan berpasir = Pasir papan (seperti papan seluncur)

Answered by arudoram | 2025-07-16