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**8 students of group 1 **
20 students of group 2 ; For this case, the first thing we must do is define variables:
x: students of group 1
y: students of group 2
We now write the system of equations that models the problem:
[ x + y = 28
y = 2x + 4 ]
Solving the system by substitution we have:
[ x + (2x + 4) = 28
3x + 4 = 28
3x = 28-4 ]
3 x = 24
[ x = \frac{24}{3}
x = 8 ]
Then, the value of y is given by:
[ y = 2 (8) +4
y = 16 + 4
y = 20 ]

Answered by carlosego | 2024-06-11

There are 20 students in one group and 8 students in the other. To represent this as an equation, x + y = 28, where y = 2x + 4. Therefore, x + 2x + 4 = 28. 3x + 4 = 28. 3x = 24. x = 24/3. x = 8. Put the x value into the y equation and it gives you 20.

Answered by W0lf93 | 2024-06-11

Group 1 has 8 students, while Group 2 has 20 students. This is derived from setting up two equations based on the problem conditions and solving them step-by-step. The solution was found by substituting and simplifying the equations.
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Answered by carlosego | 2024-10-09

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Answered by lunicyel | 2025-07-15