If the number rounds to 20, it not only is between 10 and 20, but it must be at least 15. The answer is 16 because 6 is greater than 1 by an amount of 5. Hope this helps!
The question involves a number between 10 and 20 that rounds to 20 and has one digit that is 5 greater than the other. To satisfy the condition of rounding to 20, the number must be 15 or greater since rounding rules state that if the first dropped digit is 5 or greater, the number is rounded up. Therefore, the number must be at least 15 to round up to 20.
Now, considering the second condition that one digit is 5 greater than the other, we can determine that the digits must be 1 and 6 or 2 and 7, but since the number must round to 20, we can eliminate 1 and 6 because 16 would round to 10. Hence, the only possibility is that the two digits are 2 and 7, giving us the number 17. The tens digit (1) gets rounded up to 2 because the ones digit (7) is greater than 5, according to rounding conventions.
Therefore, the number that satisfies both conditions is 17.
The number that meets the conditions of being between 10 and 20, rounding to 20, and having one digit that is 5 greater than the other is 16. It meets rounding criteria because it's above 15.5, and the digits 1 and 6 show that 6 is indeed 5 greater than 1.
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