C .3x + 4y = 153x + 2y = 12 selesai kan menggunakan metode subtitusi​

.551 .553 .552.
There ya go

Answered by gabby5792 | 2024-06-10

Three numbers between -0.55 and -0.54 are -0.549, -0.548, and -0.547.

The question asks for three numbers that are between -0.55 and -0.54.
To find such numbers, we can simply add to -0.55 by small increments that are smaller than the difference between -0.55 and -0.54, which is 0.01.
Thus, the first number could be -0.549, the second could be -0.548, and the third could be -0.547.
All three numbers are greater than -0.55 but less than -0.54, satisfying the condition.

Answered by AliciaAugello | 2024-06-24

Three numbers between -0.55 and -0.54 are -0.549, -0.5487, and -0.545. These numbers fall between the given limits on the number line. You can find many more such numbers by choosing decimals in that range.
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Answered by gabby5792 | 2024-12-26

Jawaban:x = 3y = 3/2HP = {3, 3/2}Penjelasan dengan langkah-langkah:Persamaan3x + 4y = 153x + 2y = 12 → 3x = -2y + 12Nilai y3x + 4y = 15-2y + 12 + 4y = 152y = 15 - 122y = 3y = 3/2Nilai x3x = -2y + 123x = -2(3/2) + 123x = -3 + 123x = 9x = 3Kesimpulanx = 3y = 3/2HP = {3, 3/2}[tex]\boxed{ \red{ \boxed{\pink{\mathcal{M \frak{ ilana} \purple{ \tt01}}}}}} [/tex]

Answered by Milana01 | 2025-07-16