A mass of 20 kg travels at 7 m/s and collided with a mass of 12 kg. traveling at 20 m/s in the opposite direction along the same line The coefficient of restitution is 0.7. Determine the velocities after collision

In evaporation, liquid substances become gas. So this is an example of evaporation

Answered by icedraptor88 | 2024-06-10

This is the change called evaporation, which is a type of vaporization where liquid turns to gas.

Answered by ttstreb | 2024-06-10

The change of state that causes a wet paper towel to dry is evaporation, where liquid water turns into gas. This occurs as water molecules gain energy and escape into the air. The process continues until all the liquid has evaporated, leaving the paper towel dry.
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Answered by icedraptor88 | 2024-12-26

Jawaban:v₁ = -10,21 m/s and v₂ = 8,69 m/sPenjelasan:If we set the initial direction of the first object as the positive direction, we can say that we have:[tex]\begin{aligned}m_1 &= 20\, \text{kg} \\u_1 &= +7\, \text{m/s} \\m_2 &= 12\, \text{kg} \\u_2 &= -20\, \text{m/s} \\e &= 0.7\end{aligned}[/tex]Let v₁ and v₂ be the velocity of each object after collision.From the principle of conservation of momentum, we have:[tex]\begin{aligned}m_1 u_1 + m_2 u_2 &= m_1 v_1 + m_2 v_2 \\(20)(7) + (12)(-20) &= 20v_1 + 12v_2 \\140 - 240 &= 20v_1 + 12v_2 \\-100 &= 20v_1 + 12v_2\qquad \qquad \text{...(i)}\end{aligned}[/tex]From the defiinition of coefficient of restitution, we have:[tex]\begin{aligned}e &= \frac{v_2 - v_1}{u_1 - u_2} \\0.7 &= \frac{v_2 - v_1}{7 - (-20)} \\&= \frac{v_2 - v_1}{27} \\v_2 - v_1 &= 0.7 \times 27 = 18.9 \qquad \text{...(ii)}\end{aligned}[/tex]Substitute (ii) into (i):[tex]\begin{aligned}-100 &= 20v_1 + 12v_2 \\-100 &= 20v_1 + 12(v_1 + 18.9) \\-100 &= 20v_1 + 12v_1 + 226.8 \\-100 &= 32v_1 + 226.8 \\v_1 &= \frac{-326.8}{32} \\v_1 &= \boxed{-10.2125\, \text{m/s}}\end{aligned}[/tex]Putting the value we obtained for v₁ into (ii):[tex]\begin{aligned}v_2 &= v_1 + 18.9 = -10.2125 + 18.9 = \boxed{8.6875\, \text{m/s}}\end{aligned}[/tex]Therefore, the velocity of each object after collision is:[tex]\begin{aligned}v_1 &= \boxed{-10.21\, \text{m/s}} \\v_2 &= \boxed{8.69\, \text{m/s}}\end{aligned}[/tex]Sorry for any slip or error, hope this useful.

Answered by AbdullahAlFaqir | 2025-07-18