The two numbers I will call x and y. x + y = 31 x * y = 150
You then solve for one variable in either equation and substitute it into the other equation.
x + y = 31 x = 31 - y
Then you plug it in: x * y = 150 (31 - y) * y = 150 -y² + 31y = 150 y² - 31y + 150 = 0 Then factor: (y - 6)(y - 25) = 0 y - 6 = 0 y - 25 = 0 y = 6 y = 25
When you plug y into the original equations, it comes out that the two numbers are 6 and 25. You can check your work because 6+25 = 31 and 6*25 = 150. Hope this helps! :)
To solve for two numbers when their sum and **product **are given, we can set up a system of equations and solve using substitution and algebraic methods. ;
The two numbers are 6 and 25. Their sum is 31 and their product is 150, which satisfies the conditions given in the problem. Checking the results confirms the calculations are correct.
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