Larutan NaOH 0,1 M sebanyak 200 mL direaksikan dengan 200 mL larutan MgCl₂ 0,1 M sehingga terjadi reaksi: NaOH(aq) + MgCl(aq) → Mg(OH) (s) + NaCl(aq) Jika diketahui A, Mg = 24, O = 16, dan H = 1, jumlah maksimum endapan yang dihasilkan adalah ....
Answer (3)
The maximum possible value of the decimal number before rounding to the nearest tenth and resulting in 18.6 is 18.649.
The maximum possible value of a decimal number which rounds to 18.6 to the nearest tenth can be determined using the rounding rules. When a number is rounded to the nearest tenth, the hundredths place determines if the tenths place is rounded up or remains the same. Since 18.6 is the rounded figure, the largest number it could have been before rounding would be anything up to 18.649, as rounding 18.650 and above would result in 18.7. so the correct answer is 18.649
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The maximum possible value of a decimal number that rounds to 18.6 is 18.649. This is because it must be less than 18.65, which would round up to 18.7. Therefore, 18.649 is the largest number that rounds down to 18.6.
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Jawaban:0,58 gram atau 0,01 molPenjelasan:Kita punya reaktan berupa NaOH dan MgCl₂ masing-masing sebanyak:n NaOH = 200 mL NaOH × 0,1 M = 20 mmol (milimol)n MgCl₂ = 200 mL MgCl₂ × 0,1 M = 20 mmolYang bereaksi sesuai dengan persamaan berikut (disetarakan):[tex]\displaystyle 2\,\text{NaOH(aq)} + \text{MgCl}_2\text{(aq)} \rightarrow \text{Mg(OH)}_2\text{(s)} + 2\,\text{NaCl(aq)}[/tex]Terlihat bahwa produk reaksi yang berupa padatan/solid hanya berupa Mg(OH)₂, sehingga jumlah endapan yang dihitung adalah jumlah Mg(OH)₂.Dari persamaan reaksi, terlihat bahwa tiap 2 mol NaOH dan 1 mol MgCl₂ bereaksi menghasilkan 1 mol Mg(OH)₂.Tabel jumlah mol reaksi bisa kita buat sebagai berikut.[tex]\begin{array}{l | c c c c c c c} & \text{2NaOH} & + & \text{MgCl}_2 & \rightarrow & \text{Mg(OH)}_2 & + & \text{2NaCl}\\ \cline{1-8}\text{Mula-mula} & 20\text{ mmol} & & 20\text{ mmol} & & 0 & & 0\\\text{Reaksi} & -20\text{ mmol} & & -10\text{ mmol} & & +10\text{ mmol} & & +20\text{ mmol}\\\text{Setimbang} & 0 & & 10\text{ mmol} & & 10\text{ mmol} & & 20\text{ mmol}\\\end{array}[/tex]Jumlah maksimum Mg(OH)₂ yang muncul adalah 10 mmol.Massa molar Mg(OH)₂ adalah:Mr Mg(OH)₂ = Ar Mg + (2 × Ar O) + (2 × Ar H) = 24 + 2·16 + 2·1 = 58 g/mol∴ Massa maksimum Mg(OH)₂ yang terbentuk adalah:m Mg(OH)₂ = 58 g/mol × 0,01 mol = 0,58 gram.Maaf kalau salah, semoga cukup membantu.
