larutan urea dibuat dengan melarutkan 3 gram urea ke dalam 100 gram air hitunglah molaritas dan fraksi mol air serta fraksi mol urea
Answer (3)
One thing is you need to get x on one side and y on the other :) 8x-1/3y=16 Just like any equation you subtract 8x 8x-1/3y=16 -8x -8x -1/3y=16-8x Now you want y all alone. So you divide. To me I think you divide by -3. But you might want to check and divided by by -1/3 (just in case) -1/3y=16-8x -3 y=-5.33(3 is repeating) - 2.6666667x
I really do this help you out! :D
The x-intercept of the line given by the equation 8 x − 3 1 y = 16 occurs when y = 0 . Upon substituting y = 0 into the equation and solving, we find that the x-intercept is at x = 2 , or the point ( 2 , 0 ) .
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Diketahui:- Massa urea (NH₂CONH₂) = 3 gram- Massa air (H₂O) = 100 gram- Massa molar urea (NH₂CONH₂) = 60 g/mol- Massa molar air (H₂O) = 18 g/molLangkah 1: Menghitung jumlah mol ureaJumlah mol urea = massa urea / massa molar ureaJumlah mol urea = 3 g / 60 g/molJumlah mol urea = 0,05 molLangkah 2: Menghitung jumlah mol airJumlah mol air = massa air / massa molar airJumlah mol air = 100 g / 18 g/molJumlah mol air = 5,56 molLangkah 3: Menghitung molaritas larutanMolaritas (M) = jumlah mol zat terlarut / volume larutan (dalam liter)Volume larutan tidak diberikan secara langsung, tetapi kita dapat menggunakan massa pelarut (air) dan asumsi bahwa volume larutan mendekati volume air.Volume air = massa air / densitas air ≈ 100 g / 1000 g/L = 0,1 LMolaritas = jumlah mol urea / volume larutanMolaritas = 0,05 mol / 0,1 LMolaritas = 0,5 MLangkah 4: Menghitung fraksi mol ureaFraksi mol urea = jumlah mol urea / (jumlah mol urea + jumlah mol air)Fraksi mol urea = 0,05 mol / (0,05 mol + 5,56 mol)Fraksi mol urea ≈ 0,0089Langkah 5: Menghitung fraksi mol airFraksi mol air = jumlah mol air / (jumlah mol urea + jumlah mol air)Fraksi mol air = 5,56 mol / (0,05 mol + 5,56 mol)Fraksi mol air ≈ 0,9911Ringkasan Hasil:- Molaritas larutan urea ≈ 0,5 M- Fraksi mol urea ≈ 0,0089- Fraksi mol air ≈ 0,9911
