Diketahui data binary search 5, 2, 14, 3, 7, 1, 20, 8, 15.Lakukan pencarian(Searching) untuk nilai 8 menggunakan metode Binary Search...mohon bantuannya ka

53 degrees celcius below zero is enough to freeze many substances, including water. Hope this helps!

Answered by icedraptor88 | 2024-06-10

no its not because if it was below it would have a negative

Answered by puppygirl09 | 2024-06-24

53°C below zero is equivalent to -53°C, which is significantly below the freezing point of water. This temperature results in many substances freezing, including water. It represents extremely cold conditions typically found in polar regions.
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Answered by icedraptor88 | 2025-06-14

Jawaban:Nilai 8 ditemukan pada indeks ke-5.Penjelasan dengan langkah-langkah:Urutkan data terlebih dahulu (ascending):NOTE:Ascending berarti kecil ke besar.Descending berarti besar ke kecil.Data Awal: [5, 2, 14, 3, 7, 1, 20, 8, 15]                     0, 1, 2, 3, 4, 5, 6, 7, 8 = Index (index mulai dari 0)1. Mengurutkan DataBinary Search hanya dapat dilakukan pada data yang sudah terurut.Data setelah diurutkan:[1, 2, 3, 5, 7, 8, 14, 15, 20] 0, 1, 2, 3, 4, 5, 6, 7, 8 = Index (index mulai dari 0)2. Proses Iterasi untuk Mencari Nilai 8 Iterasi 1Array: [1, 2, 3, 5, 7, 8, 14, 15, 20]Left = 0, Right = 8, Mid = (0 + 8) / 2 = 4array[4] = 7Target = 8 > 7, jadi cari di bagian kananLeft = 5, Right = 8Iterasi 2Array: [1, 2, 3, 5, 7, 8, 14, 15, 20]Left = 5, Right = 8, Mid = (5 + 8) / 2 = 6array[6] = 14Target = 8 < 14, jadi cari di bagian kiriLeft = 5, Right = 5Iterasi 3Array: [1, 2, 3, 5, 7, 8, 14, 15, 20]Left = 5, Right = 5, Mid = (5 + 5) / 2 = 5array[5] = 8Target = 8 = 8, DITEMUKAN.Pendalaman materi (TIDAK MASUK JAWABAN):Rumus Utama Binary Search:mid = (left + right) / 2Untuk Menghindari Overflow Bisa Pake Rumus Ini:mid = left + (right - left) / 2  [untuk menghindari overflow]Kondisi Pencarian:if (array[mid] == target):    return mid  //Nilai ditemukan ---> ini artinya sistem mencapai Base Case.elif (array[mid] < target):    left = mid + 1  //Jika belum mencapai nilai target maka, cari di bagian kanan -----> sistem akan terus sorting pada bagian kanan.else:    right = mid - 1  //Selanjutnya sorting akan terus dilakukan di bagian kiri.Overflow:Pada dasarnya overflow adalah kondisi ketika nilai dari kedua int ditambahkan dan melibihi kapasitas dari integer itu tersebut.Contoh:int a = 2,000,000,000int b = 1,000,000,000int hasil = a + b  // 3,000,000,000Tapi maksimal int (32-bit) = 2,147,483,647Karena 3,000,000,000 > 2,147,483,647 maka OVERFLOW.

Answered by aekmohop | 2025-07-17