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In Kimia / Sekolah Menengah Atas | 2025-07-17

Hitunglah maritas 400 mi laruton Yang mengandung 20 gram Naoh! dengan O = 16, H = 1 arwo.23

Asked by IkrhyDamayanthy9881

Answer (4)

There can only be one reason for that . . . making something tough out of something easy.
-19 = x - 7
How could you get 'x' all by itself on one side, and everything else on the other side ?
What if you add 7 to each side ?
Then you have *** -12 = x *** . To your amazement, that's the solution !

Answered by AL2006 | 2024-06-10

-19=x-7 -19+7=x-7+7 -12=x

Answered by lfarrukee | 2024-06-10

To solve − 19 = x − 7 , add 7 to both sides to isolate x . This results in x = − 12 . Checking the solution confirms it is correct as both sides of the equation are equal when substituted back.
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Answered by AL2006 | 2024-12-26

Jawaban:Jadi, molaritas larutan NaOH adalah 1,25 M.Penjelasan:Hitunglah molaritas 400 mL larutan yang mengandung 20 gram NaOH!Diketahui:- Massa NaOH = 20 gram- Volume larutan = 400 mL = 0,4 L- Massa molar NaOH:  - Na = 23 g/mol  - O = 16 g/mol  - H = 1 g/molMassa molar NaOH = 23 + 16 + 1 = 40 g/molLangkah-langkah perhitungan:1. Hitung jumlah mol NaOH:   Jumlah mol = Massa / Massa molar   Jumlah mol = 20 gram / 40 g/mol   Jumlah mol = 0,5 mol2. Hitung molaritas (M):   Molaritas (M) = Jumlah mol / Volume larutan (dalam liter)   Molaritas = 0,5 mol / 0,4 L   Molaritas = 1,25 MJadi, molaritas larutan NaOH adalah 1,25 M.

Answered by pupusdwisuryoanggono | 2025-07-18