Jika sebuah kereta bergerak ke arah utara dengan kecepatan 100 km/jam dan angin bertiup ke arah barat dengan kecepatan 50 km/jam, ke arah mana asap kereta akan bergerak?
Answer (4)
The normal daily input of water is about 2.5 L from beverages food, and metabolism. The normal daily output of 2.5 L consists of 1.8 L in urine, sweat, and feces, plus 0.7 L in insensible water loss. Insensible water loss is water that evaporates through the skin and from the respiratory tract. Insensible losses account for 0.7 L of water loss per day. The average human exhales an average of 0.35 L of water each day. This corresponds to about 14% of water lost through respiration.
It's about 10 to 20 percent
Approximately 14% of daily water loss occurs through the respiratory system, which equates to about 0.35 liters daily. This water loss is part of the overall daily output of approximately 2.5 liters from the body. Understanding this process helps us recognize the importance of hydration in our overall health.
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Jawaban:Penjelasan:Agar sesuai dengan koordinat polar yang dipakai untuk menyatakan vektor maka arah timur diberi adalah arah 0°, utara 90°, barat 180°, selatan 270°(-90°)Diketahui:[tex]\overline v_k=100\text {kmh}^{-1}\angle 270^{\circ} \to \text {kecepatan asap ke selatan}\\\overline v_a=50\text {kmh}^{-1}\angle 180^{\circ} \to \text {kecepatan asap ke selatan}[/tex]Ditanyakan:[tex]\overline v_r=?[/tex]Alternatif penyelesaian:[tex]v_r=\sqrt{v_k^2+v_a^2} \\v_r=\sqrt{100^2+50^2} \,\,\text{kmh}^{-1}\\v_r=10\sqrt{10^2+5^2} \,\,\text{kmh}^{-1}\\v_r=10\sqrt{100+25} \,\,\text{kmh}^{-1}\\v_r=10\sqrt{125} \,\,\text{kmh}^{-1}\\v_r=10\sqrt{25\cdot 5} \,\,\text{kmh}^{-1}\\v_r=50\sqrt{5} \,\,\text{kmh}^{-1}[/tex][tex]\tan \theta=\frac{v_k}{v_s} \\\tan \theta=\frac{100}{50} \\\tan \theta= 2\\\theta=243,43^{\circ}[/tex][tex]\overline v_r=50\sqrt{5\,\,} \angle 243,43^{\circ}[/tex]Jadi asap kereta bergerak dengan kecepatan 50√5 kearah 243.43° barat daya.
