sebuah roda berputar pada sudut 30⁰ dengan gaya 120 n dengan jari-jari roda 50 cm apabila massa roda 8 kg hitungla momen gaya dan momen torsinya​

6 c ...........2.40$ 10 c ........... x x = 6 2.40 ∗ 10 ​ = 6 24.0 ​ x = 4$ ​

Answered by mariamikayla | 2024-06-10

2.40/6= 0.4 0.4*10= $4 Hope this helps :)

Answered by Bekamop99 | 2024-06-10

The cost of one cake is $0.40. Therefore, the cost of 10 cakes is $4.00.
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Answered by mariamikayla | 2024-12-26

Penjelasan:diberi:sudut = 30° (tapi ni tak payah pakai sgt pun utk kira momen)gaya (F) = 120 Njari-jari (r) = 50 cm = 0.5 mmassa (m) = 8 kgnak cari:1. momen gaya (moment of force)2. momen inersia (momen tegar)3. momen tork (torque)---1. momen gaya (τ)rumus:> τ = F × r × sin(θ)θ = 30°, sin(30°) = 0.5τ = 120 × 0.5 × 0.5 = 30 Nm---2. momen inersia (I)untuk roda pejal (solid disk), rumus:> I = ½ × m × r²I = ½ × 8 × (0.5)² = ½ × 8 × 0.25 = 1 kgm²---3. momen tork = momen gaya = 30 Nm(ni sama je sebab momen tork = τ)---so jawapan akhir:momen gaya = 30 Nmmomen inersia = 1 kgm²momen tork = 30 Nm

Answered by sayasukamatematiklah | 2025-07-18