bagaimana kondisi sebuah benda yang memiliki massa 50 gr dan volume nya 25 cm^3 jika dimasukkan ke dalam air yang massa jenisnya 1gr / cm^ 3​

6.807 × 1 0 13
To get this answer count the number of space you have between the first 0 to 6 and put a decimal between 6 and 8.
6*** 8,070,000,000,000 ***
*11,12,13,10 987 654 321
You count 13 right
*

Answered by baybay5010 | 2024-06-10

Okay at the end there will be a decimal 68,070,000,000,000. (well it doesn't have to but anyway) You want to move the decimal between 6 and 8 because in scientific notation the number has to be between 1 and 10
6.8070000000000 (Now count how many places it takes to get 6.8, I got 13 moves)
So now you want to make the 13 an exponent to 10. (I'm really I'm sorry, I answer this type of question before and I can't really explain it clearly but I know how O_O, anyway...)
it will be 6.807 x 10 ¹³
***I hope this help you out and sorry about me not really explaining it like you wanted to... :( ***

Answered by sydneyhenderson | 2024-06-10

The number 68,070,000,000,000 can be expressed in scientific notation as 6.807 × 10¹³, obtained by moving the decimal point 13 places to the left of the first non-zero digit, which is 6.807.
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Answered by baybay5010 | 2024-12-26

Penjelasan:rumus dia:ketumpatan = jisim ÷ isipadu= 50 g ÷ 25 cm³= 2 g/cm³air punya ketumpatan = 1 g/cm³ jeso bila kita bandingkan:ketumpatan benda > ketumpatan airbenda tu lagi tumpat dari airmaksudnya benda tu akan tenggelam bila dimasukkan dalam airplease brainliest answers

Answered by sukamatematik0 | 2025-07-18