Berapakah volum larutan H2SO4 yang terbentuk dari 46 gram H2SO4 (Ar H = 1 ; S = 32 ; O = 16) menjadi larutan H2SO4 2,5 M?

32∣2 16∣2 8 ∣2 4 ∣2 2 ∣2 1 32 = 2 5 80∣2 40∣2 20∣2 10∣2 5 ∣5 1 80 = 2 4 ∗ 5 H . C . F ( 32 ; 80 ) = 2 4 = 16

Answered by mariamikayla | 2024-06-10

16 ;

Answered by jasminerosecollins54 | 2024-06-13

The highest common factor (HCF) of 32 and 80 is found by using prime factorization. The prime factorization shows that 32 is 2 5 and 80 is 2 4 × 5 1 . Thus, the HCF is the smallest power of the common prime factor, which is 2 4 = 16 .
;

Answered by mariamikayla | 2024-12-24

===========================================PERHITUNGAN VOLUME LARUTAN H2SO4 - NOTEPAD===========================================Soal:Berapakah volume larutan H2SO4 yang terbentuk dari 46 gram H2SO4(Ar H = 1 ; S = 32 ; O = 16) menjadi larutan H2SO4 2,5 MLangkah-langkah:1. Hitung Mr (massa molar) H2SO4: Mr = (2 × H) + (1 × S) + (4 × O) = (2 × 1) + (1 × 32) + (4 × 16) = 2 + 32 + 64 = 98 gram/mol2. Hitung mol H2SO4: mol = massa / Mr = 46 / 98 ≈ 0,469 mol3. Gunakan rumus Molaritas: M = mol / volume (L) Maka: Volume = mol / M = 0,469 / 2,5 ≈ 0,1876 liter4. Ubah ke mililiter: 0,1876 liter = 187,6 mLJawaban:Volume larutan H2SO4 yang terbentuk adalah ± 187,6 mL

Answered by pupusdwisuryoanggono | 2025-07-19