mumbuat soal tentang magnet berserta rumusnyaBuat soal magnet 3 soal ttg hitungan ​

The abolitionist movement was a movement in the United States and also in Europe that sought to abolish or end the slave trade and to free slaves. Two early abolitionists in the United States were Thomas Jefferson and Benjamin Franklin, however, their positions were rather contradictory given that each was a slaveholder. Benjamin Franklin was a leading member of the Pennsylvania Society for the Abolition of Slavery, a leading early abolitionist organization. Later in the 1800s the abolitionist movement in the North was led by social reformers such as William Lloyd Garrison founder of the American Anti-Slavery Society. Additionally writers like Harriet Beecher Stowe and John Greenleaf Whittier were also active abolitionists. There were also many black abolitionist activists such as Frederick Douglass and Charles Henry Langston. The Emancipation Proclamation issued during the Civil War freed slaves in the confederate states, however, slavery was not officially ended until the 13th Amendment was passed in December 1865 which outlawed slavery.

Answered by Gibbs | 2024-06-10

The abolition movement, which aimed to end slavery, was shaped by key figures like William Lloyd Garrison and Frederick Douglass, as well as pivotal events such as the American Revolution and the Civil War. The movement significantly influenced American society and led to the eventual passing of the 13th Amendment, which abolished slavery. Its legacy continues to inspire various social justice movements today.
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Answered by Gibbs | 2024-10-30

Jawaban:Berikut adalah 3 contoh soal hitungan tentang magnet beserta rumusnya dan jenis pembahasan:---✅ Soal 1: Gaya Magnetik pada Kawat BerarusSoal:Sebuah kawat lurus panjang dialiri arus listrik sebesar 5 A dan berada dalam medan magnet sebesar 0,2 T tegak lurus arah arus. Jika panjang kawat dalam medan magnet adalah 0,4 m, hitung besar gaya magnetik yang dialami kawat tersebut!Rumus: F = B × I × L × sinθDimana:F = gaya magnetik (N)B = kuat medan magnet (T)I = arus listrik (A)L = panjang kawat (m)θ = sudut antara arus dan medan (tegak lurus → sin 90° = 1)Jawaban:F = 0,2 × 5 × 0,4 × 1 = 0,4 N---✅ Soal 2: Gaya Lorentz pada Muatan BergerakSoal:Sebuah partikel bermuatan q = 3 × 10⁻⁶ C bergerak dengan kecepatan v = 2 × 10⁵ m/s dalam medan magnet B = 0,1 T dengan arah tegak lurus medan. Hitung besar gaya Lorentz yang dialami partikel!Rumus: F = q × v × B × sinθ(Sudut tegak lurus → sin 90° = 1)Jawaban:F = 3 × 10⁻⁶ × 2 × 10⁵ × 0,1 = 0,06 N---✅ Soal 3: Kuat Medan Magnet di Sekitar KawatSoal:Sebuah kawat lurus panjang dialiri arus I = 10 A. Hitung kuat medan magnet (B) di titik yang berjarak r = 2 cm (0,02 m) dari kawat!Rumus: B = (μ₀ × I) / (2π × r)μ₀ = permeabilitas vakum = 4π × 10⁻⁷ T·m/AJawaban:B = (4π × 10⁻⁷ × 10) / (2π × 0,02)B = (4 × 10⁻⁶) / 0,04 = 1 × 10⁻⁴ TPenjelasan:√Apakah membantu?

Answered by 63mawati | 2025-07-20