63|3 \\ 21|3 \\ 7 \ |7 \\ 1 \\\\ 63=3^2*7 \\\\ 63-composite \ number \ because \ it \ can \ be \ divided \ by \ D_{63=\{1;3;7;9;21;63 \}
The answer is composite because a prime number is only divisible by 1 and itself. You can divide sixty-three by 9, 7,21,3,63, and 1.
The number 63 is a composite number because it has more than two positive divisors. Specifically, it can be divided by 1, 3, 7, 9, 21, and itself (63). Therefore, it is not a prime number.
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