jika vektor F1 panjangnya 12 satuan dan F2 panjangnya 10 satuan tentukan panjang resultan kedua vektor tersebut jika membentuk sudut 60°​

Rounding a number to the nearest hundred can be determined by the digit in the tenths place. If the digit in the tenths place is between 0 and 4, the number should be rounded down. If the digit in the tenths place is between 5 and 9, the number should be rounded up. In this case, the number has a digit in the tenths place that is between 5 and 9. Therefore, 684 should be rounded up to 700.

Answered by Anonymous | 2024-06-10

Rounding 684 to the nearest hundred gives 700 . To round **684 **to the nearest hundred, look at the tens digit .
The tens digit of 684 is 8, which is greater than or equal to 5. Increase the **hundreds digit **by 1 and replace the tens and units digits with zeros.
The term "hundreds digit" refers to the digit that occupies the hundreds place in a number. In a whole number, each digit represents a specific place value .
For example, in the number 523, the digit 5 is in the hundreds place, the digit 2 is in the tens place, and the digit 3 is in the ones place.
Therefore, Rounding **684 **to the nearest hundred gives 700 .
To learn more about tens digit , follow the link:
https://brainly.com/question/30142622
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Answered by hbsinghvt | 2024-06-17

Rounding 684 to the nearest hundred results in 700. This is done by looking at the tens digit, which is 8, and since it is greater than 5, we round up the hundreds digit from 6 to 7. Hence, we replace the tens and units digits with zeros, getting 700.
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Answered by hbsinghvt | 2024-09-27

Jawaban:Penjelasan:Diketahui:[tex]F_1=12\\F_2=10\\\theta=60^{\circ}[/tex]Ditanyakan:[tex]F=?[/tex]Alternatif penyelesaian:[tex]F=\sqrt{(F_1+F_2\cos\theta)^2+(F_1+F_2\sin\theta)^2} \\F=\sqrt{(12+10\cos60^{\circ})^2+(12+10\sin60^{\circ})^2} \\F=\sqrt{(12+10(\frac{1}{2}) )^2+(12+10(\frac{1}{2}\sqrt{3} ) })^2} \\F=\sqrt{(12+5) )^2+(12+5\sqrt{3} })^2} \\F=\sqrt{289+144+120\sqrt{3}+75 } \\F=\sqrt{508+120\sqrt{3} } \\F=2\sqrt{127+30\sqrt{3} }[/tex]Jadi panjang resultan kedua vektor adalah [tex]2\sqrt{127+30\sqrt{3} }[/tex] satuan.Gunakan kalkulator jika diinginkan hasil dalam desimal.

Answered by mastreeada | 2025-07-20