2. Hitunglah jumlah mol dari: a. 15 gram CaCO3 b. 17,1 gram C12H22O11 3. Hitunglah: 1,7 gram NH3 =........mol NH3 = .......mol N = .......mol H = .......molekul NH3​

8 ( 4 x − 5 ) − 12 = 20 x − 10
32 x − 40 − 12 = 20 x − 10
32 x − 52 = 20 x − 10
32 x − 52 − 20 x = − 10
12 x − 52 = − 10
12 x = − 10 + 52
12 x = 42
x = 12 42 ​
x = 2 7 ​
x = 3 2 1 ​ ≈ 3.5

Answered by rabinshrestha41 | 2024-06-10

8 ( 4 x − 5 ) − 12 = 20 x − 10 32 x − 40 − 12 = 20 x − 10 12 x = 42 x = 12 42 ​ = 2 7 ​

Answered by konrad509 | 2024-06-10

To solve ( 2 x ) 2 = 4.0 ( 1 − x ) 2 , take the square root of both sides, simplify the equations, and find that the only solution is x = 2 1 ​ . The second case results in a contradiction, confirming our original solution. Therefore, x = 2 1 ​ is the sole solution.
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Answered by rabinshrestha41 | 2024-12-26

Jawaban:===========================================PERHITUNGAN MOL DAN MOLEKUL===========================================2. Hitung jumlah mol dari:a. 15 gram CaCO₃ - Mr CaCO₃ = 40 (Ca) + 12 (C) + 16×3 (O) = 100 - Mol = massa / Mr = 15 / 100 = **0,15 mol**b. 17,1 gram C₁₂H₂₂O₁₁ (sukrosa/gula) - Mr C₁₂H₂₂O₁₁ = (12×12) + (1×22) + (16×11) = 144 + 22 + 176 = 342 - Mol = 17,1 / 342 = **0,05 mol**-------------------------------------------3. Hitunglah:a. 1,7 gram NH₃ - Mr NH₃ = 14 (N) + 3×1 (H) = 17 - Mol NH₃ = 1,7 / 17 = **0,1 mol**b. Mol N dalam NH₃ - 1 mol NH₃ mengandung 1 mol N - Jadi, 0,1 mol NH₃ = **0,1 mol N**c. Mol H dalam NH₃ - 1 mol NH₃ mengandung 3 mol H - Jadi, 0,1 mol NH₃ × 3 = **0,3 mol H**d. Molekul NH₃ - 1 mol = 6,022 × 10²³ molekul - 0,1 mol × 6,022×10²³ = **6,022 × 10²² molekul NH₃**===========================================

Answered by pupusdwisuryoanggono | 2025-07-20